Optimal. Leaf size=44 \[ \frac{B \tanh ^{-1}(\sin (c+d x))}{a d}-\frac{(B-C) \sin (c+d x)}{d (a \cos (c+d x)+a)} \]
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Rubi [A] time = 0.165926, antiderivative size = 44, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.1, Rules used = {3029, 2978, 12, 3770} \[ \frac{B \tanh ^{-1}(\sin (c+d x))}{a d}-\frac{(B-C) \sin (c+d x)}{d (a \cos (c+d x)+a)} \]
Antiderivative was successfully verified.
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Rule 3029
Rule 2978
Rule 12
Rule 3770
Rubi steps
\begin{align*} \int \frac{\left (B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^2(c+d x)}{a+a \cos (c+d x)} \, dx &=\int \frac{(B+C \cos (c+d x)) \sec (c+d x)}{a+a \cos (c+d x)} \, dx\\ &=-\frac{(B-C) \sin (c+d x)}{d (a+a \cos (c+d x))}+\frac{\int a B \sec (c+d x) \, dx}{a^2}\\ &=-\frac{(B-C) \sin (c+d x)}{d (a+a \cos (c+d x))}+\frac{B \int \sec (c+d x) \, dx}{a}\\ &=\frac{B \tanh ^{-1}(\sin (c+d x))}{a d}-\frac{(B-C) \sin (c+d x)}{d (a+a \cos (c+d x))}\\ \end{align*}
Mathematica [B] time = 0.247445, size = 109, normalized size = 2.48 \[ \frac{2 \cos \left (\frac{1}{2} (c+d x)\right ) \left ((C-B) \sec \left (\frac{c}{2}\right ) \sin \left (\frac{d x}{2}\right )+B \cos \left (\frac{1}{2} (c+d x)\right ) \left (\log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )-\log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )\right )\right )}{a d (\cos (c+d x)+1)} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.053, size = 78, normalized size = 1.8 \begin{align*} -{\frac{B}{da}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) }-{\frac{B}{da}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) -1 \right ) }+{\frac{B}{da}\ln \left ( \tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) +1 \right ) }+{\frac{C}{da}\tan \left ({\frac{dx}{2}}+{\frac{c}{2}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.21704, size = 134, normalized size = 3.05 \begin{align*} \frac{B{\left (\frac{\log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a} - \frac{\log \left (\frac{\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a} - \frac{\sin \left (d x + c\right )}{a{\left (\cos \left (d x + c\right ) + 1\right )}}\right )} + \frac{C \sin \left (d x + c\right )}{a{\left (\cos \left (d x + c\right ) + 1\right )}}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.67426, size = 197, normalized size = 4.48 \begin{align*} \frac{{\left (B \cos \left (d x + c\right ) + B\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) -{\left (B \cos \left (d x + c\right ) + B\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \,{\left (B - C\right )} \sin \left (d x + c\right )}{2 \,{\left (a d \cos \left (d x + c\right ) + a d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{B \cos{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}}{\cos{\left (c + d x \right )} + 1}\, dx + \int \frac{C \cos ^{2}{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}}{\cos{\left (c + d x \right )} + 1}\, dx}{a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.57954, size = 96, normalized size = 2.18 \begin{align*} \frac{\frac{B \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right )}{a} - \frac{B \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right )}{a} - \frac{B \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - C \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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